3[p+2(p-2)]=4(p-3)

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Solution for 3[p+2(p-2)]=4(p-3) equation:


Simplifying
3[p + 2(p + -2)] = 4(p + -3)

Reorder the terms:
3[p + 2(-2 + p)] = 4(p + -3)
3[p + (-2 * 2 + p * 2)] = 4(p + -3)
3[p + (-4 + 2p)] = 4(p + -3)

Reorder the terms:
3[-4 + p + 2p] = 4(p + -3)

Combine like terms: p + 2p = 3p
3[-4 + 3p] = 4(p + -3)
[-4 * 3 + 3p * 3] = 4(p + -3)
[-12 + 9p] = 4(p + -3)

Reorder the terms:
-12 + 9p = 4(-3 + p)
-12 + 9p = (-3 * 4 + p * 4)
-12 + 9p = (-12 + 4p)

Add '12' to each side of the equation.
-12 + 12 + 9p = -12 + 12 + 4p

Combine like terms: -12 + 12 = 0
0 + 9p = -12 + 12 + 4p
9p = -12 + 12 + 4p

Combine like terms: -12 + 12 = 0
9p = 0 + 4p
9p = 4p

Solving
9p = 4p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-4p' to each side of the equation.
9p + -4p = 4p + -4p

Combine like terms: 9p + -4p = 5p
5p = 4p + -4p

Combine like terms: 4p + -4p = 0
5p = 0

Divide each side by '5'.
p = 0

Simplifying
p = 0

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